Given a natural number x and n different coin values c1 … cn, compute in how many ways it is possible to achieve change x by using each value at most twice. Here, two coins with the same value are considered different.
For example, if x = 4 and the available values are 1 and 2, then there are three ways to achieve it: 1 + 1′ + 2, 1 + 1′ + 2′, and also 2 + 2′.
Input
Input consists of several cases. Every case begins with x and n, followed by c1 … cn. Assume 1 ≤ n ≤ 20, 1 ≤ ci ≤ x ≤ 1000, and that all ci are different.
Output
For every case print, in lexicographic order, all possible ways to exactly achieve change x by using each value at most twice. Print every solution with its values sorted from small to big. In doing that, assume 1 < 1′ < 2 < 2′ < …. Use “1p” to print 1′, etcetera. Print a line with 10 dashes at the end of every case.
Hint
A simply pruned backtracking should be enough.
Input
4 2 1 2 400 1 200 400 1 300 5 3 4 2 1 5 5 1 2 3 4 5
Output
4 = 1 + 1p + 2 4 = 1 + 1p + 2p 4 = 2 + 2p ---------- 400 = 200 + 200p ---------- ---------- 5 = 1 + 2 + 2p 5 = 1 + 4 5 = 1 + 4p 5 = 1p + 2 + 2p 5 = 1p + 4 5 = 1p + 4p ---------- 5 = 1 + 1p + 3 5 = 1 + 1p + 3p 5 = 1 + 2 + 2p 5 = 1 + 4 5 = 1 + 4p 5 = 1p + 2 + 2p 5 = 1p + 4 5 = 1p + 4p 5 = 2 + 3 5 = 2 + 3p 5 = 2p + 3 5 = 2p + 3p 5 = 5 5 = 5p ----------