A permutation p1, …, pn is a sequence of numbers between 1 and n such that each number appears exactly once. An inversion in a permutation is a pair of indices (i, j) such that i < j but pi > pj. The weight of an inversion (i, j) is j − i.
How many permutations of n elements exist where the sum of weights of all inversions is equal to x? For instance, there are exactly two such permutations for n = 4 and x = 4: 3, 2, 1, 4 and 1, 4, 3, 2.
Input
Input consists of several cases, each one with n and x. You can assume 1 ≤ n ≤ 14 and 0 ≤ x ≤ (n + 1)n(n − 1)/6.
Output
For every case, print the number of permutations of n elements such that the sum of weights of all inversions is x.
Input
4 4 1 0 14 455 14 200
Output
2 1 1 486253544