The one of the coins P87919


Statement
 

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Perhaps you have read that some problems are so classic that they barely need a statement. For this one, given a collection of n coins with different values and a target amount A, we ask you to indicate the way to add up to A by using coins of the largest possible values. In particular, a way is better than another one if the former uses more coins of the largest value; in the event of a tie, if it uses more coins of the second largest value, etc.

Input

Input consists of several cases. Each case begins with the number of coins n between 1 and ‍100, followed by n different integer numbers v1, …, vn, where 1≤ vi≤ 10000. Finally, we have an integer number 1≤ A≤ 100000.

Output

For every case, print in non-increasing order the necessary coins to get A, choosing the combination with coins of largest value in case of a tie. If there is no solution, print −1.

Public test cases

  • Input

    8
1 2 5 10 25 50 100 200
481

3
1 4 5
5

6
428 19 521 67 84 101
75

6
428 19 521 67 84 101
749

    Output

    200,200,50,25,5,1
5
-1
521,19,19,19,19,19,19,19,19,19,19,19,19
    • Information
    Author
    Omer Giménez
    Language
    English
    Translator
    Carlos Molina
    Original language
    Spanish
    Other languages
    Spanish
    Official solutions
    C++
    User solutions
    C++ Python