Cool vector X90362

Statement

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To solve this problem you have to complete the code that you will find at the end of the statement. You have to replace each ??? with an expression of code. Do not change anything else. Download from the website of the problem the file code.cc with the code to be completed (click on the corresponding button “.CPP”), edit it and submit it to the judge. We also provide you with a file main.cc to help you when testing your solution, which you must not submit to the judge.

In this problem, we say that a vector with n integer numbers v[0..n−1] is cool if n ≥ 2, v[0] > v[n−1], and there exists an index j between 0 and n−2 such that:

v[0] ≤ … ≤ v[j−1] ≤ v[j],
v[j+1] ≤ v[j+2] ≤ … ≤ v[n−1].

For instance, the vector [12, 12, 15, 20, 1, 3, 3, 5, 9] is cool (with j = 3).

Implement an efficient function

int search(int x, const vector<int>& v);

that returns the position of the last occurrence of x in a cool vector v. If x does not belong to v, return a -1.

Precondition

The vector v is cool.

#include <iostream> #include <vector> using namespace std; int position(const vector<int>& v, int e, int d) { if (e+1 == d) return e; int m = (e+d)/2; if (???) return position(v, m, d); else return position(v, e, m); } int search(int x, const vector<int>& v, int e, int d) { if (e > d) return -1; if (e == d) return (v[e] == x ? e : -1); int m = ??? // Pay attention when d == e + 1 if (???) return search(x, v, e, ???); else return search(x, v, ???, d); } int search(int x, const vector<int>& v) { int n = v.size(); int j = position(v, 0, n-1); int p = search(x, v, 0, j); if (p != -1) return p; return search(x, v, j+1, n-1); }

Information

Author: Enric Rodríguez
Language: English
Translator: Enric Rodríguez
Original language: Catalan
Other languages: Catalan
Official solutions: C++
User solutions: C++